1.
Page 325
Problem 5
(a) use
centered formula of order O(
)
![]()
(b) use
centered formula of order O(
)
![]()
(c) ![]()
![]()
2.
Page 364
Problem 3(a)
for ![]()
![]()
since ![]()
so, ![]()
suppose ![]()
(1) approximate the surface area using the composite trapezoidal rule with M=10.
![]()

(2) approximate the surface area using the composite simpson rule with M=5.
![]()

3.
Page 423
Problem 6
the distance between a point (
)and a line
is:

the line is

so,

so the distance between any point (x,y) on circle and this line is:

here (x,y) also satisfy ![]()
so that ![]()

solve ![]()

![]()
so ![]()
![]()
We have 4 possible points:
(1.09756, 4.878049)
(1.09756, -4.878049)
(-1.09756, 4.878049)
(-1.09756, -4.878049)
![]()
![]()
![]()
![]()
thus, the point on the circle which is farthest from the
chord AB is (-1.09756, -4.878049)
4.
Page 440
Problem 5
(a)
(1) h=0.2



(2)h=0.1





(b) exact
solution ![]()
(c) F.G.E
![]()
![]()
![]()
So the F.G.E behaves as expected when h is halved.
5.
Page 448
Problem 4
(a)
· h=0.2



· h=0.1





(b) exact solution ![]()
(c) F.G.E
![]()
![]()
![]()
So the F.G.E behaves as expected when h is halved.
6.
Page 457
Problem 5
(a)
![]()
![]()
![]()
![]()
h=0.1

![]()

![]()

![]()

![]()
(b)
exact solution is ![]()
7.
Page 471
Problem 4
(a)
![]()
· h=0.2


![]()

![]()
· h=0.1


![]()

![]()

![]()

![]()
(b) exact solution ![]()
(c) F.G.E
![]()
![]()
![]()
So the F.G.E behaves as expected when h is halved.
8.
Page 494 Problem
8
(a) Reformulate
![]()
![]()
use substitution
, then ![]()
the differential equation becomes a system:

with ![]()
(b) Programming result:
(Courtesy of Alan
T. Saunders)
Enter the left end point of the interval: 0
Enter the right end point of the interval: 2
Enter the number of steps: 40
Input the initial value of
: 2
Input the initial value of
: 3

(c) (Courtesy of Alan
T. Saunders)



